QUICK, Help PLEASE! NEEDED FAST! 20 POINTS!
In this triangle, what is the value of x?

Enter your answer, rounded to the nearest tenth, in the box.

QUICK Help PLEASE NEEDED FAST 20 POINTS In this triangle what is the value of x Enter your answer rounded to the nearest tenth in the box class=

Respuesta :

Since you have the side opposite of x and the hypotenuse, and
[tex] \sin(x) = \frac{opposite}{hypotenuse} [/tex]
you have

[tex] \sin(x) = \frac{66}{79} [/tex]
Now solve for x.
[tex]x = \arcsin( \frac{66}{79} ) [/tex]
Another way to write arcsin() is
[tex] \sin^{ - 1} () [/tex]
In either case, plug that into your calculator and you'll find that
[tex]x = 56.7 ^{o} [/tex]
Make sure your calculator is in degree mode and not radian mode.