The volume of a right square pyramid is [tex]V= \frac{1}{3} A_{\text{ basis } }\cdot h[/tex], where [tex]A_{\text{ basis } }[/tex] is basis area.
If the lengths of the sides of the base remain fixed and height
is multiplied by a factor 10, than new height is [tex]H=10h[/tex] and the volume is
[tex]V^{\ast}=A_{\text{ basis } }\cdot H=\frac{1}{3} A_{\text{ basis } }\cdot 10h=\frac{10}{3} A_{\text{ basis } }\cdot h[/tex]
