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The area of a rectangle is found by multiplying the base times the height. A rectangle with an area represented by 12x2 + 6x – 8 has a height of 4x. What is the base of the rectangle? 3x + – 3x2 + – 3x + – 3x + –

Respuesta :

[tex]\bf \textit{area of a rectangle}\\\\ A=bh~~ \begin{cases} b=base\\ h=height\\ ---------\\ A=12x^2+6x-8\\ h=4x \end{cases}\implies 12x^2+6x-8=b(4x) \\\\\\ \cfrac{12x^2+6x-8}{4x}=b\implies \cfrac{12x^2}{4x}+\cfrac{6x}{4x}-\cfrac{8}{4x}=b\implies 3x+\cfrac{3}{2}-\cfrac{2}{x}=b[/tex]

its B on edge-nuity just took the test