Evaluate the function g(x) = –2x2 + 3x – 5 for the input values –2, 0, and 3. g(–2) = –2(–2)2 + 3(–2) – 5 g(–2) = –2(4) – 6 – 5 g(–2) = g(0) = g(3) =

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Input values just means to input them in for 'x' in your function.

[tex]\sf g(x)=-2x^2+3x-5[/tex]

[tex]\sf g(-2)=-2(-2)^2+3(-2)-5[/tex]

Simplify:

[tex]\sf g(-2)=-2(4)-6-5[/tex]

[tex]\sf g(-2)=-8-6-5[/tex]

[tex]\boxed{\sf g(-2)=-19}[/tex]

[tex]\sf g(x)=-2x^2+3x-5[/tex]

[tex]\sf g(0)=-2(0)^2+3(0)-5[/tex]

Simplify:

[tex]\sf g(0)=-2(0)-5[/tex]

[tex]\boxed{\sf g(0)=-5}[/tex]

[tex]\sf g(x)=-2x^2+3x-5[/tex]

[tex]\sf g(3)=-2(3)^2+3(3)-5[/tex]

Simplify:

[tex]\sf g(3)=-2(9)+9-5[/tex]

[tex]\sf g(3)=-18+9-5[/tex]

[tex]\boxed{\sf g(3)=-14}[/tex]

The result of the function if x = -2, 0 and 3 are -19, -5 and -14 respectively

GIven the function g(x) = –2x^2 + 3x – 5

If x = -2, then;

g(-2) = –2(-2)^2 + 3(-2) – 5

g(-2) = -2(4) - 6 - 5

g(-2) = -19

If x = 0, then;

g(0) = –2(0)^2 + 3(0) – 5

g(0) = -2(0) - 0 - 5

g(0) = -5

If x = 3, then;

g(3) = –2(3)^2 + 3(3) – 5

g(3) = -2(9) + 9 - 5

g(3) = -14

Hence the result of the function if x = -2, 0 and 3 are -19, -5 and -14 respectively

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