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An urn contains different colored marbles. The probability of drawing two green marbles from the urn without replacement is 320 , and the probability of drawing one green marble is 25 .

What is the probability of drawing a second green marble, given that the first marble is green?




38

350

15

12

Respuesta :

The answer is B,350Hope this helps!

The probability of taking out a second green marble when the first given marble is green would be:

B). 3/50

As we know,

Probability(P) = No. of favorable outcomes/Total no. of outcomes

Given that,

The Probability(P) of taking out two green marble is [tex]3/20[/tex]

The Probability(P) of taking out one green marble is [tex]2/5[/tex]

To find,

The Probability(P) of taking out a second green marble when the first given marble is green [tex]= 3/20[/tex] × [tex]2/5[/tex]

[tex]= (3[/tex] × [tex]2)/(20[/tex] × [tex]5)[/tex]

[tex]= 6/100[/tex]

[tex]= 3/50[/tex]

Thus, option B is the correct answer.

Learn more about "Probability" here:

brainly.com/question/10322288

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