Ahh yes, negative exponents always give us a scare once and a while. All the negative means is to flip the position of its base. For instance, if x has a negative exponent and x in the denominator, all you would have to do is move x to the numerator with the same power (except it's no longer negative). Before we substitute x and all the other variables which the values given, let's eliminate the negatives first.
After flipping positions/eliminating the negative exponents it should look like this:
[tex] \frac{ 2^{2} x^{3} }{ y^{5} } [/tex]
which simplifies to
[tex] \frac{ 4 x^{3} }{ y^{5} } [/tex]
now that everything is simplified, and all negative exponents are eliminated we can substitute x with 2, and y with (-4).
[tex] \frac{4 (2)^{3} }{ (-4)^{5} } [/tex]
which simplifies to
[tex] \frac{4(8)}{(-1024)} = \frac{32}{-1024} = - \frac{1}{32} [/tex]
Final Answer: - \frac{1}{32} [/tex]
