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A group of people were surveyed, and the data about their age and whether they have an iron deficiency was recorded in the two-way frequency table.

Based on the data in the table, the probability of randomly choosing a person who has iron deficiency and is less than 20 years old is 1.) _____ . The
probability of randomly choosing a person who does not have iron deficiency and is more than 20 years old is 2.) _____ .

Chooses For #1 =

1-A.) 0.14
1-B.) 0.27
1-C.) 0.4

Chooses For #2 =

2-A.) 0.15
2-B.) 0.23
2-C.) 0.3

A group of people were surveyed and the data about their age and whether they have an iron deficiency was recorded in the twoway frequency table Based on the da class=

Respuesta :

Answer:

1-A.) 0.14 ; 2-C.) 0.3

Step-by-step explanation:

There are 41 people less than 20 years old who have an iron deficiency.  There are 300 total people.  This gives us the probability

41/300 = 0.136666 ≈ 0.14

There are 43+46 = 89 people greater than 20 years old who do not have an iron deficiency.  There are 300 total people.  This gives us the probability

89/300 = 0.29666 ≈ 0.30 = 0.3

JeanaShupp

Answer: 1-A.) 0.14

2-C.) 0.3

Step-by-step explanation:

1.) The number of persons who have iron deficiency and is less than 20 years old  =41

The total number of persons surveyed = 3000

Thus, the probability of randomly choosing a person who has iron deficiency and is less than 20 years old [tex]=\frac{41}{300}=0.136666666667\approx0.14[/tex]

Hence, the  probability of randomly choosing a person who has iron deficiency and is less than 20 years old = 0.14

2.) The number of persons who do not have iron deficiency and is more than 20 years old  =43+46=89

Thus, the probability of randomly choosing a person who do not have iron deficiency and is more than 20 years old [tex]=\frac{89}{300}=0.296666666667\approx0.30[/tex]

Hence, the probability of randomly choosing a person who do not have iron deficiency and is more than 20 years old =0.3

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