Given quadratic equation : [tex]0 = 4x^2+2x- 1[/tex]
Let us apply standard quadratic form [tex]0=ax^2+bx+c[/tex]
We know, quadratic formula
[tex]x = \frac{-b+-\sqrt{b^2-4ac}}{2a}[/tex]
a = 4
b = 2
c= -1
Now we plug in all the values in quadratic formula
[tex]x = \frac{-b+-\sqrt{b^2-4ac}}{2a} \\ x = \frac{-2+-\sqrt{2^2-4(4)(-1)}}{2(4)}\\ x = \frac{-2+-\sqrt{18}}{8}[/tex].
The above one is the substitution of values of a,b,c in quadratic formula.
