Oliver’s room is 3 yards wide. The perimeter of the room is 14 yards.What is the area of Oliver’s room?

Respuesta :

The perimeter of a rectangle is twice the sum of length and width. Oliver's room must have a length and width that total (14 yd)/2 = 7 yd. Then the length is
  7 yd - 3 yd = 4 yd

The area is the product of length and width, so is
  (4 yd)×(3 yd) = 12 yd²