What is the emf produced in a 1.5 meter wire moving at a speed of 6.2 meters/second perpendicular to a magnetic field of strength 3.96 × 10-3newtons/amp·meter?
General formula for emf is : emf = vBL (sin 0)...(1) As the angle here is 90º and sin90º =1. So, equation (1) becomes : emf = vBL Putting values : emf = (6.2)(1.5)(3.96 * 10^-3) = 0.0369 volts Hope this helps:)
