jasmineturner2 jasmineturner2
  • 04-06-2018
  • Chemistry
contestada

if a gas is initially at 5.50 atm, 121 L, 293 K, then it changes to 5.15 atm and 298 K, what is the new volume?

Respuesta :

kenmyna
kenmyna kenmyna
  • 13-06-2018
  The new volume  of the gas  is  131.43   liters
    
                    calculation

This is calculated  by use of combined  gas law equation

that is p1V1/T1 = P2V2/T2

P1 = 5.50  atm
V1= 121 L
T1= 293  k
P2=   5.15  atm
T2 = 298 K
V2 =?

by  making V2 the   subject of the  formula

V2=  T2 P1V1/ P2T1


V2  is therefore =  (298 k x 5.50  atm   x121 L)/  (  5.15  atm  x 293 k)  = 131.43  L
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