Respuesta :

konrad509
[tex]t\geq-273\\\\ 358=20\sqrt{273+t}\\ 17.9=\sqrt{273+t}\\ 320.41=273+t\\ t=47.41\approx47[/tex]
gmany
[tex]v=20\sqrt{273+t};\ t > 0[/tex]
We have
[tex]v=358\ m/s[/tex]
substitute
[tex]20\sqrt{273+t}=358\ \ \ |:20\\\\\sqrt{273+t}=17.9\ \ \ |square\ both\ sides\\\\273+t=320.41\ \ \ \ |-273\\\\t=47.41\approx47[/tex]
Answer: 47°C