Answer is: Ka for phenol (C₆H₅OH) is 2.67·10⁻¹¹.
Chemical reaction: C₆H₅OH(aq) + H₂O(l) → C₆H₅O⁻(aq) + H₃O⁺(aq) or C₆H₅OH(aq) ⇄ C₆H₅O⁻(aq) + H⁺(aq). Ka = [C₆H₅O⁻] · [H⁺] / [C₆H₅OH]. [H⁺] = [C₆H₅O⁻] = 2.340·10⁻⁶ M; equilibrium concentration. [C₆H₅OH] = 0.205 M - 2.340·10⁻⁶ M. [C₆H₅OH] = 0.20499 M. Ka = (2.340·10⁻⁶ M)² ÷ 0.20499 M. Ka = 2.67·10⁻¹¹.
