Respuesta :

kanest

There are 50 total patrons. 16 like lattes, 12 like espressos, and 8 like both drinks.

Add the two totals for patrons that like either lattes or espressos:

[tex] 16 + 12 = 28 [/tex]

8 patrons like both drinks, so subtract this from the amount of patrons that like either drink:

[tex] 28 - 8 = 20 [/tex]

20 patrons like at least one drink.

Subtract the amount of patrons that like a drink from the total amount of patrons:

[tex] 50 - 20 = \boxed{30} [/tex]

30 patrons like neither drink.
First we need to find the number of Patrons who like either Latte or Espresso.

n(L) = 16
n(E) = 12
n(L and E) = 8

n(L or E) = n(L) + n(E) - n(L and E)

n(L or E) = 16 + 12 - 8 = 20

Thus 20 like Either of the coffee drinks.

The patrons don't like either of the drinks will be = 50 - 20 = 30

So, option D gives the correct answer

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