As the shape of the pool is circular,
So area of the pool = [tex] \prod \times r^{2} [/tex]
radius = r = 3 yards
Area of the pool = [tex] \prod \times 3^{2} [/tex]
Area of the pool = [tex] \prod \times 9 [/tex]
Area of the pool = [tex] 9\prod [/tex]
So area of two pools of same size = [tex] 2 \times 9\prod [/tex]
Area of two pools of same size = [tex] 18 \prod [/tex]
[tex] \prod [/tex] = 3.14
Area of two pools of same size = [tex] 3.14 \times 18 [/tex]
Area of two pools of same size = 56.52 sq. yd
Area of two pools of same size = 56.5 sq. yd
