contestada

I have 345 mL of a 1.5 M NaCl solution. If I boil the water until the volume of the solution is 250 mL, what will the molarity of the solution be:?

Respuesta :

Eduard22sly

The final molarity of the solution will be 2.07 M

From the question given above, the following data were obtained:

  • Initial volume (V₁) = 345 mL
  • Initial molarity (M₁) = 1.5 M
  • Final volume (V₂) = 250 mL
  • Final molarity (M₂) =?

The final molarity of the solution can be obtained as follow:

M₁V₁ = M₂V₂

1.5 × 345 = M₂ × 250

517.5 = M₂ × 250

Divide both side by 250

M₂ = 517.5 / 250

M₂ = 2.07 M

Thus, the final molarity of the solution is 2.07 M

Learn more about molarity: https://brainly.com/question/25838405

samueladesida43

The molarity of the new solution prepared will be 2.07 M

HOW TO CALCULATE MOLARITY:

  • The molarity of a solution can be calculated using the following expression:

M₁V₁ = M₂V₂

Where;

  1. M1 = initial concentration
  2. M2 = final concentration
  3. V1 = initial volume
  4. V2 = final volume

According to this question, the following data were given:

  1. Initial volume (V₁) = 345 mL
  2. Initial molarity (M₁) = 1.5 M
  3. Final volume (V₂) = 250 mL
  4. Final molarity (M₂) =?

  • The molarity of the solution can be obtained as follow:

M₁V₁ = M₂V₂

1.5 × 345 = M₂ × 250

517.5 = M₂ × 250

M₂ = 517.5 / 250

M₂ = 2.07 M

Therefore, the molarity of the new solution is 2.07 M.

Learn more about molarity at: https://brainly.com/question/12127540