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a city us growing at the rate of 0.9% annually. if there were 3619000 residents in yhe city in 1994, find how many to the nearest ten thousand are living in that city in 2000. use y=3619000(2.7)^0.009t

Respuesta :

carlosego
For this case we have the following equation:
 y = 3619000 (2.7) ^ 0.009t
 We must evaluate the equation for the year 2000.
 Therefore, we must replace the following value of t:
 t = 2000 - 1994
 t = 6
 Substituting we have:
 y = 3619000 (2.7) ^ (0.009 * 6)
 y = 3818407.078
 Round to the nearest ten thousand:
 y = 3820000
 Answer:
 3820000 residents are living in that city in 2000