Respuesta :
n; n+1 - two consecutive numbers
n + (n + 1) = 131n + n + 1 = 1312n + 1 = 131 |-12n = 130 |:2n = 65n+1 = 66
Answer: 65 and 66.
n + (n + 1) = 131n + n + 1 = 1312n + 1 = 131 |-12n = 130 |:2n = 65n+1 = 66
Answer: 65 and 66.
The sum of two consecutive numbers is 131. What are the two numbers?
Answer is provided in the image attached.
