In this fulcrum, for the weights to be balance, what do the distances d1 and d2 have to be if the overall length is 12 feet?
D1= 6.55 ft./ 5.45 ft./ 7.20 ft.
D2= 5.45 ft./ 6.55 ft./ 4.80 ft.

In this fulcrum for the weights to be balance what do the distances d1 and d2 have to be if the overall length is 12 feet D1 655 ft 545 ft 720 ft D2 545 ft 655 class=

Respuesta :

For the fulcrum to balance, the product of weight and distance on both sides of the fulcrum must be the same.

Let d1= x. since total distance is 12, we can write d2 = 12 - x

for the fulcrum to balance:

60x = 50(12 - x)

60x = 600 - 50x

110x = 600

x = 5.45

Thus, d1= 5.45
and
d2= 12 - d1 = 12 - 5.45 = 6.55

d1 = 5.45
d2 = 6.55
For this case we have the following system of equations:
 Equilibrium equation:
 60 * d1 = 50 * d2
 Total distance:
 d1 + d2 = 12
 Solving the equations we have:
 d1 = 5.45 feet
 d2 = 6.55 feet
 Answer:
 
the distances d1 and d2 have to be:
 d1 = 5.45 feet
 d2 = 6.55 feet