Let the station 1 as S1 and station 2 as S2. (please refer the diagram)
Distance between S1 and S2 = 25 miles
∠S2S1P = 73° and ∠S1S2P = 46°
So ∠S1PS2 = 180 - (73 +46) = 61°
According to the diagram, to find S2P we will use a sine law
[tex] \frac{sin 73}{S2P} = \frac{sin 61}{S1S2}
\\\\
\frac{0.9563}{S2P} = \frac{0.8746}{25}\\\\[/tex]
Cross multiply
[tex]0.9563\times 25 = 0.8746 \times S2P\\\\
23.9075 = 0.8746 \times S2P\\\\[/tex]
Divide both side by 0.8746
[tex]\frac{23.9075}{0.8746} = S2P\\\\
S2P= 27.33 [/tex]
So distance between the plane and station 2 is 27.33 miles
