Respuesta :
Answer:
The answer is - 2) 1248
Step-by-step explanation:
A bowl has the shape of a hemisphere whose diameter is 14 centimeters.
So, radius is 7 cm.
The volume of the hemisphere is given by = [tex]\frac{2}{3} \pi r^{3}[/tex]
=> [tex]\frac{2}{3} *3.14*7*7*7[/tex] = 718 cubic cm
Now, the weight of the water that can be contained in the bowl =
[tex]718\times1.25=897.50[/tex]
And the total weight of water plus bowl = [tex]350+897.50=1247.50[/tex] or rounding this to 1248 grams.
The total weight of the bowl and liquid is 1248 grams.
It is given that
Diameter of the bowl = 14 cm
Weight of the bowl = 350grams
The density of the fluid = 1.25 grams per cubic centimeter
What is the volume of a hemisphere?
The volume of a hemisphere with radius r is 2/3 πr³.
Total weight= weight of the bowl + weight of the liquid.
Weight of the liquid = density of liquid * volume of liquid.
The volume of liquid = volume of the hemisphere with radius 7cm.
The volume of liquid = [tex]\frac{2}{3} *\pi *r^3[/tex]
The volume of liquid = 2/3 * π* 7³=718.67 cubic centimeter.
Weight of the liquid = density*volume = 718.67*1.25 = 898 grams
So, the total weight will be 350+898 = 1248 grams.
Therefore, the total weight of the bowl and liquid is 1248 grams.
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