Answer:
0.50 g of Na Metal
Solution:
The equation for given reaction is as follow,
2 NaN₃ → 2 Na + 3 N₂
According to equation,
When,
67.2 L (3 mole) N₂ is produced along with = 46 g (2 mole) of Na Metal
So,
0.744 L N₂ produced will accompany = X g of Na Metal
Solving for X,
X = (0.744 L × 46 g) ÷ 67.2 L
X = 0.50 g of Na Metal
