we can use the ideal gas law equation to find the number of moles of gas PV = nRT where P - standard pressure - 101 325 Pa V -volume - 15.0 x 10⁻³ m³ n - number of moles R - universal gas constant - 8.314 Jmol⁻¹K⁻¹ T - standard temperature - 273 K substituting the values in the equation 101 325 Pa x 15.0 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 273 K n = 0.670 mol
molecular mass of the gas can be calculated as follows molar mass = mass / number of moles = 55.50 g / 0.670 mol molecular mass of gas is 82.8 g/mol
Answer is: the molar mass of gas is 82.83 g/mol. m(gas) = 55.50 g; mass of gas. V(gas) = 15.0 L; volume of gas. Vm = 22.4 L/mol; molar volume of gas on STP. n(gas) = V(gas) ÷ Vm. n(gas) = 15 L ÷ 22.4 L/mol. n(gas) = 0.67 mol; amount of gas. M(gas) = m(gas) ÷ n(gas). M(gas) = 55.5 g ÷ 0.67 mol. M(gas) = 82.83 g/mol.
