We know the sum of all angles in a triangle is [tex]180^{ \circ}[/tex] and they have given both the triangles two of the angles.
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For the one on the right, we have
[tex]53+80=133[/tex]
[tex]180-133=47[/tex]
The bottom left angle of the triangle on the right is [tex]47^{ \circ}[/tex].
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For the triangle on the left, we do the same process.
The bottom right angle of the triangle on the left is [tex]68^{ \circ}[/tex].
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Now we can find the last angle of the smaller triangle created by the overlapping larger triangles.
Using the same method as the previous ones, we get
[tex]65^{ \circ}[/tex].
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A straight angle is [tex] 180^{ \circ} [/tex].
[tex]180-65=\boxed{115}[/tex]
[tex]x=115[/tex]
