Determine whether the function is odd, even or neither: f(x) = (x - 2)³ + 3
My original working was:
f(-x) = ((-x) - 2)³ + 3 = (-x - 2)³ + 3
= (-x³ - 3(-x)²x 2 + 3(-x) × (2)² - (2)³) + 3
= (-x³ - 6x² - 12x - 8) + 3
= - (x³ + 6x² + 12x + 5)
= -f(x) :.
odd However I know this is wrong as the function is neither even or odd. Could someone please tell me where I went wrong and show me the correct working. Thank you!