The television show CSI: Shoboygan has been successful for many years. That show recently had a share of 15, which means, that among the TV sets in use, 15% were tuned to CSI: Shoboygan. An advertiser wants to verify that 15% share value by conducting its own survey, and a pilot survey begins with 11 households have TV sets in use at the time of a CSI: Shoboygan broadcast.
Find the probability that none of the households are tuned to CSI: Shoboygan. P(none) =
Find the probability that at least one household is tuned to CSI: Shoboygan. P(at least one) = Find the probability that at most one household is tuned to CSI: Shoboygan. Plat most one) =
If at most one household is tuned to CSI: Shoboygan, does it appear that the 15% share value is wrong? (Hint: Is the occurrence of at most one household tuned to CSI: Shoboygan unusual?)
a. Yes, it appears to be wrong, Observing at most one household tuned to CSI: Shoboygan would be unusual to see if the show had a share of 15%.
b. No, it does not seem wrong. It is still reasonable to observe at most one household tuned to CSI: Shoboygan given a 15% share.