Hydrazoic acid (HN3) ionizes in aqueous solution, as represented in the equation above. If the percent ionization of HN3 in a 2.0 M HN3(aq) solution is 0.35%, what is the acid dissociation constant Ka of HN3(aq)?
HN3(aq) + H2O(l) <--> N3-(aq) + H3O+(aq) Ka = ?
4.1 x 104
2.5 x 10-5
2.5 x 10-1
3.5 x 10-3