Evaluate the indefinite integral by using the substitution \nu=\sqrt(x)-4. What is the value of \int((\sqrt(x)-4)^(6))/(2\sqrt(x))dx?

A) -\frac{1}{8}(\sqrt(x)-4)^7+C
B) \frac{1}{8}(\sqrt(x)-4)^7+C
C) \frac{1}{8}(\sqrt(x)-4)^6+C
D) -\frac{1}{8}(\sqrt(x)-4)^6+C