In the problem we worked through in the text, we found that 223.4 grams of iron requires 426 grams of chlorine gas to react with, on the reactant side of the balanced chemical equation. But we must be able to do these problems from the reactant side to the product side as well. Let's bring back the balanced equation. 2Fe + 3Cl₂ 2FeCl3 What if we're asked: How many grams of FeCl3 are produced when 426 grams of chlorine react with iron, according to this equation? Well, we first have to convert the mass of chlorine to moles. How many moles of Cl₂ are we starting with? Select one: a. 1 mole b. 4 moles c. 6 moles d. 8.5 moles​