Coach Roberts has a device that launches baseballs into the air so the outfielders can practice catching pop-ups. If it launches a ball with a velocity of 100100​​ feet per second, after how many seconds will the ball be at a height of 120120​​ feet above the ground? Use the equation for projectile motion h=-16 t^{2}+v0t where h​ is the height of the ball t​ seconds after it is launched at an initial velocity of v0