Given the thermochemical equations
X₂ + 3 Y₂ → 2XY3 ΔH1= -340kJ
X₂ + 2Z₂ → 2XZ₂ ΔH2= -170 kJ
2Y2 + Z2 → 2Y₂Z ΔH3= -260 kJ

Calculate the change in enthalpy for the reaction.

4XY3 +7Z₂ → 6Y₂Z + 4 XZ₂

ΔH= ____ kJ